Sports | March 19, 2020 7:00 am

Report: Tom Brady Picked Buccaneers Because of His Son Jack

The veteran QB has a 12-year-old with his ex-girlfriend Bridget Moynahan

Tom Brady walking across the field in AFC Wild Card game
Tom Brady of the New England Patriots before the AFC Wild Card Playoff game against the Tennessee Titans in January 2020.
Maddie Meyer/Getty

Take it with a $60 million (or more) grain of salt, but The New York Post is reporting the primary reason Tom Brady chose to sign with the Tampa Bay Buccaneers is because of his 12-year-old son Jack.

Brady shares Jack with his New York City-based ex-girlfriend Bridget Moynahan and, while he reportedly considered other teams farther from Jack’s NYC home, he chose Tampa Bay to stay close to his son.

Brady, who has two children with wife Gisele Bündchen, dated Blue Bloods actress Moynahan from 2004 until 2006.

“It was between three teams and he’s going with the Buccaneers. They’ll likely announce it on Thursday or Friday,” a source told the Post. “A lot of [the reason for his choice] had to do with proximity to New York. Jack lives in New York and [Brady] wants to be close to his son.”

Though the details of Brady’s deal with the Buccaneers haven’t yet been revealed, it’s believed he has agreed to a roughly $30 million-per-year deal with Tampa Bay for at least two seasons.

Far-fetched as it may be, the Post’s report meshes with a previous report from ESPN’s Jeff Darlington that “good weather and favorable proximity to NYC for personal reasons” were both factors in Brady’s decision.

That’s all well and good, but it’s not exactly as if Tampa Bay is the sixth borough of New York City after Brooklyn, Queens, Manhattan, Staten Island and the Bronx.

Brady may indeed want to be close to his son, but he also wanted to be far away from Bill Belichick and New England in the AFC — and be well-compensated for it.

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